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-4x^2+1=5x+2
We move all terms to the left:
-4x^2+1-(5x+2)=0
We get rid of parentheses
-4x^2-5x-2+1=0
We add all the numbers together, and all the variables
-4x^2-5x-1=0
a = -4; b = -5; c = -1;
Δ = b2-4ac
Δ = -52-4·(-4)·(-1)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-3}{2*-4}=\frac{2}{-8} =-1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+3}{2*-4}=\frac{8}{-8} =-1 $
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